There are few Math Problem Solving Strategies. In stead of taking up the lengthy method to solve a math problem, we can adopt the short method which will save our time and energy.
Strategy : 1 >>> Multiplication by breaking up numbers :
Let us take an example of multiplication of two big numbers.
8142 x 131 = what?
131 can be restructured into 100 + 10 + 10 + 11
8142 x 131 = (8141) x (100 + 10 + 10 + 11)
(8141) x (100 + 10 + 10 + 11) =
8141 x 100 = 814100
8141 x 10 = 81410
Add these numbers.
8141 x 110 = 814100 + 81410 = 895510
(8141 x 11) = (8141 x 110)/10 = 895510/10 = 89551
Add this to 895510.
895510 + 89551 = 985061
8141 x (100 + 10 + 11) = 985061
8141 x 10 = 81410
8141 x (100 + 10 + 11 + 10) = 985061 + 81410 = 1066471
8141 x 131 = 985061 + 81410 = 1066471
Strategy : 2 >>> To multiply a number by 1001 :
256 x 1001 = what?
In this write 256 two times continuously. That is the answer.
256 x 1001 = 256256
453 x 1001 = 453453
108 x 1001 = 108108
800 x 1001 = 800800
669 x 1001 = 669669
123 x 1001 = 123123
963 x 1001 = 963963
Strategy : 3 >>> To multiply by 11 :
132 x 11 = what?
Step 1 : Prefix zero and suffix zero to the multiplicand.
Step 2 : Write down the answer from right to left.
The digits of the answer are got by adding two successive digits of the multiplicand, its right neighbour.
In case you come across any two digit number in the step of addition, put down only the right digit and carry the left digit.
132 x 11 =
Prefix zero and suffix zero to the multiplicand (132).
132 >>> 01320
0 + 1 = 1
1 + 3 = 4
3 + 2 = 5
2 + 0 = 2
132 x 11 = 1452
Strategy : 4 >>> To multiply by 12 :
This is same as the previous one (Strategy : 3) except that you have to double each number before you add the right neighbour.
132 x 12 = what?
Prefix zero and suffix zero to the multiplicand (132).
132 >>> 01320
(0 x 2) + 1 = 0 + 1 = 1
(1 x 2) + 3 = 2 + 3 = 5
(3 x 2) + 3 = 6 + 2 = 8
(2 x 2) + 0 = 4 + 0 = 4
132 x 12 = 1584
Strategy : 5 >>> Square of a number :
To find out the square of a 2-digit number, take the nearest multiple of 10. Rewrite the 2-digit number ad addition and subtraction of the nearest multiple of 10.
Then the calculation is done as following.
43
2 = 43 x 43
The nearest multiples of 10 for 43 are 40 and 50.
43 = 43 x 43 = (40 + 3) x (46 - 3)
= (40 + 3) x (50 - 7)
= (40 x 46) – (3 x -7)
= (1840) – (-9)
= 1840 + 9
= 1849
43
2 = 1849
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